Theorem rneq 4579

Description: Equality theorem for range. (Contributed by NM, 29-Dec-1996.)

Assertion

Ref	Expression
rneq	⊢ (𝐴 = 𝐵 → ran 𝐴 = ran 𝐵)

Proof of Theorem rneq

Step	Hyp	Ref	Expression
1		cnveq 4527	. . 3 ⊢ (𝐴 = 𝐵 → ◡𝐴 = ◡𝐵)
2	1	dmeqd 4555	. 2 ⊢ (𝐴 = 𝐵 → dom ◡𝐴 = dom ◡𝐵)
3		df-rn 4374	. 2 ⊢ ran 𝐴 = dom ◡𝐴
4		df-rn 4374	. 2 ⊢ ran 𝐵 = dom ◡𝐵
5	2, 3, 4	3eqtr4g 2138	1 ⊢ (𝐴 = 𝐵 → ran 𝐴 = ran 𝐵)

Syntax hints:   → wi 4   = wceq 1284  ^◡ccnv 4362  dom cdm 4363  ran crn 4364

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 662  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-10 1436  ax-11 1437  ax-i12 1438  ax-bndl 1439  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468  ax-ext 2063

This theorem depends on definitions:  df-bi 115  df-3an 921  df-tru 1287  df-nf 1390  df-sb 1686  df-clab 2068  df-cleq 2074  df-clel 2077  df-nfc 2208  df-v 2603  df-un 2977  df-in 2979  df-ss 2986  df-sn 3404  df-pr 3405  df-op 3407  df-br 3786  df-opab 3840  df-cnv 4371  df-dm 4373  df-rn 4374

This theorem is referenced by:  rneqi  4580  rneqd  4581  xpima1  4787  feq1  5050  foeq1  5122