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Theorem bifal 1497
Description: A contradiction is equivalent to falsehood. (Contributed by Mario Carneiro, 9-May-2015.)
Hypothesis
Ref Expression
bifal.1 ¬ 𝜑
Assertion
Ref Expression
bifal (𝜑 ↔ ⊥)

Proof of Theorem bifal
StepHypRef Expression
1 bifal.1 . 2 ¬ 𝜑
2 fal 1490 . 2 ¬ ⊥
31, 22false 365 1 (𝜑 ↔ ⊥)
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 196  wfal 1488
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 197  df-tru 1486  df-fal 1489
This theorem is referenced by:  falantru  1508  ralnralall  4080  tgcgr4  25426  frgrregord013  27253  bj-df-nul  33017  bicontr  33879  aibnbaif  41074  aifftbifffaibif  41088  atnaiana  41090
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