Theorem xpcogend 13713

Description: The most interesting case of the composition of two cross products. (Contributed by RP, 24-Dec-2019.)

Hypothesis

Ref	Expression
xpcogend.1	⊢ (𝜑 → (𝐵 ∩ 𝐶) ≠ ∅)

Assertion

Ref	Expression
xpcogend	⊢ (𝜑 → ((𝐶 × 𝐷) ∘ (𝐴 × 𝐵)) = (𝐴 × 𝐷))

Proof of Theorem xpcogend

Dummy variables 𝑥 𝑧 𝑦 are mutually distinct and distinct from all other variables.

Step	Hyp	Ref	Expression
1		xpcogend.1	. . . . . 6 ⊢ (𝜑 → (𝐵 ∩ 𝐶) ≠ ∅)
2		n0 3931	. . . . . . 7 ⊢ ((𝐵 ∩ 𝐶) ≠ ∅ ↔ ∃𝑦 𝑦 ∈ (𝐵 ∩ 𝐶))
3		elin 3796	. . . . . . . 8 ⊢ (𝑦 ∈ (𝐵 ∩ 𝐶) ↔ (𝑦 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶))
4	3	exbii 1774	. . . . . . 7 ⊢ (∃𝑦 𝑦 ∈ (𝐵 ∩ 𝐶) ↔ ∃𝑦(𝑦 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶))
5	2, 4	bitri 264	. . . . . 6 ⊢ ((𝐵 ∩ 𝐶) ≠ ∅ ↔ ∃𝑦(𝑦 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶))
6	1, 5	sylib 208	. . . . 5 ⊢ (𝜑 → ∃𝑦(𝑦 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶))
7	6	biantrud 528	. . . 4 ⊢ (𝜑 → ((𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐷) ↔ ((𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐷) ∧ ∃𝑦(𝑦 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶))))
8		brxp 5147	. . . . . . 7 ⊢ (𝑥(𝐴 × 𝐵)𝑦 ↔ (𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵))
9		brxp 5147	. . . . . . . 8 ⊢ (𝑦(𝐶 × 𝐷)𝑧 ↔ (𝑦 ∈ 𝐶 ∧ 𝑧 ∈ 𝐷))
10		ancom 466	. . . . . . . 8 ⊢ ((𝑦 ∈ 𝐶 ∧ 𝑧 ∈ 𝐷) ↔ (𝑧 ∈ 𝐷 ∧ 𝑦 ∈ 𝐶))
11	9, 10	bitri 264	. . . . . . 7 ⊢ (𝑦(𝐶 × 𝐷)𝑧 ↔ (𝑧 ∈ 𝐷 ∧ 𝑦 ∈ 𝐶))
12	8, 11	anbi12i 733	. . . . . 6 ⊢ ((𝑥(𝐴 × 𝐵)𝑦 ∧ 𝑦(𝐶 × 𝐷)𝑧) ↔ ((𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵) ∧ (𝑧 ∈ 𝐷 ∧ 𝑦 ∈ 𝐶)))
13	12	exbii 1774	. . . . 5 ⊢ (∃𝑦(𝑥(𝐴 × 𝐵)𝑦 ∧ 𝑦(𝐶 × 𝐷)𝑧) ↔ ∃𝑦((𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵) ∧ (𝑧 ∈ 𝐷 ∧ 𝑦 ∈ 𝐶)))
14		an4 865	. . . . . 6 ⊢ (((𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵) ∧ (𝑧 ∈ 𝐷 ∧ 𝑦 ∈ 𝐶)) ↔ ((𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐷) ∧ (𝑦 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶)))
15	14	exbii 1774	. . . . 5 ⊢ (∃𝑦((𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵) ∧ (𝑧 ∈ 𝐷 ∧ 𝑦 ∈ 𝐶)) ↔ ∃𝑦((𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐷) ∧ (𝑦 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶)))
16		19.42v 1918	. . . . 5 ⊢ (∃𝑦((𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐷) ∧ (𝑦 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶)) ↔ ((𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐷) ∧ ∃𝑦(𝑦 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶)))
17	13, 15, 16	3bitri 286	. . . 4 ⊢ (∃𝑦(𝑥(𝐴 × 𝐵)𝑦 ∧ 𝑦(𝐶 × 𝐷)𝑧) ↔ ((𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐷) ∧ ∃𝑦(𝑦 ∈ 𝐵 ∧ 𝑦 ∈ 𝐶)))
18	7, 17	syl6rbbr 279	. . 3 ⊢ (𝜑 → (∃𝑦(𝑥(𝐴 × 𝐵)𝑦 ∧ 𝑦(𝐶 × 𝐷)𝑧) ↔ (𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐷)))
19	18	opabbidv 4716	. 2 ⊢ (𝜑 → {⟨𝑥, 𝑧⟩ ∣ ∃𝑦(𝑥(𝐴 × 𝐵)𝑦 ∧ 𝑦(𝐶 × 𝐷)𝑧)} = {⟨𝑥, 𝑧⟩ ∣ (𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐷)})
20		df-co 5123	. 2 ⊢ ((𝐶 × 𝐷) ∘ (𝐴 × 𝐵)) = {⟨𝑥, 𝑧⟩ ∣ ∃𝑦(𝑥(𝐴 × 𝐵)𝑦 ∧ 𝑦(𝐶 × 𝐷)𝑧)}
21		df-xp 5120	. 2 ⊢ (𝐴 × 𝐷) = {⟨𝑥, 𝑧⟩ ∣ (𝑥 ∈ 𝐴 ∧ 𝑧 ∈ 𝐷)}
22	19, 20, 21	3eqtr4g 2681	1 ⊢ (𝜑 → ((𝐶 × 𝐷) ∘ (𝐴 × 𝐵)) = (𝐴 × 𝐷))

Syntax hints:   → wi 4   ∧ wa 384   = wceq 1483  ∃wex 1704   ∈ wcel 1990   ≠ wne 2794   ∩ cin 3573  ∅c0 3915   class class class wbr 4653  {copab 4712   × cxp 5112   ∘ ccom 5118

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-9 1999  ax-10 2019  ax-11 2034  ax-12 2047  ax-13 2246  ax-ext 2602  ax-sep 4781  ax-nul 4789  ax-pr 4906

This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-3an 1039  df-tru 1486  df-ex 1705  df-nf 1710  df-sb 1881  df-clab 2609  df-cleq 2615  df-clel 2618  df-nfc 2753  df-ne 2795  df-ral 2917  df-rex 2918  df-rab 2921  df-v 3202  df-dif 3577  df-un 3579  df-in 3581  df-ss 3588  df-nul 3916  df-if 4087  df-sn 4178  df-pr 4180  df-op 4184  df-br 4654  df-opab 4713  df-xp 5120  df-co 5123

This theorem is referenced by:  xpcoidgend  13714