Theorem sbcbii 2873

Description: Formula-building inference rule for class substitution. (Contributed by NM, 11-Nov-2005.)

Hypothesis

Ref	Expression
sbcbii.1	⊢ (𝜑 ↔ 𝜓)

Assertion

Ref	Expression
sbcbii	⊢ ([𝐴 / 𝑥]𝜑 ↔ [𝐴 / 𝑥]𝜓)

Proof of Theorem sbcbii

Step	Hyp	Ref	Expression
1		sbcbii.1	. . . 4 ⊢ (𝜑 ↔ 𝜓)
2	1	a1i 9	. . 3 ⊢ (⊤ → (𝜑 ↔ 𝜓))
3	2	sbcbidv 2872	. 2 ⊢ (⊤ → ([𝐴 / 𝑥]𝜑 ↔ [𝐴 / 𝑥]𝜓))
4	3	trud 1293	1 ⊢ ([𝐴 / 𝑥]𝜑 ↔ [𝐴 / 𝑥]𝜓)

Syntax hints:   ↔ wb 103  ⊤wtru 1285  [wsbc 2815

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-5 1376  ax-7 1377  ax-gen 1378  ax-ie1 1422  ax-ie2 1423  ax-8 1435  ax-11 1437  ax-4 1440  ax-17 1459  ax-i9 1463  ax-ial 1467  ax-i5r 1468  ax-ext 2063

This theorem depends on definitions:  df-bi 115  df-tru 1287  df-nf 1390  df-sb 1686  df-clab 2068  df-cleq 2074  df-clel 2077  df-sbc 2816

This theorem is referenced by:  eqsbc3r  2874  sbc3an  2875  sbccomlem  2888  sbccom  2889  sbcabel  2895  csbco  2917  sbcnel12g  2923  sbcne12g  2924  sbccsbg  2934  sbccsb2g  2935  csbnestgf  2954  csbabg  2963  sbcssg  3350  sbcrel  4444  difopab  4487  sbcfung  4945  f1od2  5876  mpt2xopovel  5879  bezoutlemnewy  10385  bezoutlemstep  10386  bezoutlemmain  10387