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Theorem staffn 18849
Description: The functionalization is equal to the original function, if it is a function on the right base set. (Contributed by Mario Carneiro, 6-Oct-2015.)
Hypotheses
Ref Expression
staffval.b  |-  B  =  ( Base `  R
)
staffval.i  |-  .*  =  ( *r `  R )
staffval.f  |-  .xb  =  ( *rf `  R )
Assertion
Ref Expression
staffn  |-  (  .*  Fn  B  ->  .xb  =  .*  )

Proof of Theorem staffn
Dummy variable  x is distinct from all other variables.
StepHypRef Expression
1 dffn5 6241 . . 3  |-  (  .*  Fn  B  <->  .*  =  ( x  e.  B  |->  (  .*  `  x
) ) )
21biimpi 206 . 2  |-  (  .*  Fn  B  ->  .*  =  ( x  e.  B  |->  (  .*  `  x
) ) )
3 staffval.b . . 3  |-  B  =  ( Base `  R
)
4 staffval.i . . 3  |-  .*  =  ( *r `  R )
5 staffval.f . . 3  |-  .xb  =  ( *rf `  R )
63, 4, 5staffval 18847 . 2  |-  .xb  =  ( x  e.  B  |->  (  .*  `  x
) )
72, 6syl6reqr 2675 1  |-  (  .*  Fn  B  ->  .xb  =  .*  )
Colors of variables: wff setvar class
Syntax hints:    -> wi 4    = wceq 1483    |-> cmpt 4729    Fn wfn 5883   ` cfv 5888   Basecbs 15857   *rcstv 15943   *rfcstf 18843
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-8 1992  ax-9 1999  ax-10 2019  ax-11 2034  ax-12 2047  ax-13 2246  ax-ext 2602  ax-sep 4781  ax-nul 4789  ax-pow 4843  ax-pr 4906  ax-un 6949
This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-3an 1039  df-tru 1486  df-ex 1705  df-nf 1710  df-sb 1881  df-eu 2474  df-mo 2475  df-clab 2609  df-cleq 2615  df-clel 2618  df-nfc 2753  df-ne 2795  df-ral 2917  df-rex 2918  df-rab 2921  df-v 3202  df-sbc 3436  df-dif 3577  df-un 3579  df-in 3581  df-ss 3588  df-nul 3916  df-if 4087  df-pw 4160  df-sn 4178  df-pr 4180  df-op 4184  df-uni 4437  df-br 4654  df-opab 4713  df-mpt 4730  df-id 5024  df-xp 5120  df-rel 5121  df-cnv 5122  df-co 5123  df-dm 5124  df-rn 5125  df-res 5126  df-ima 5127  df-iota 5851  df-fun 5890  df-fn 5891  df-f 5892  df-fv 5896  df-staf 18845
This theorem is referenced by: (None)
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