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Theorem f0rn0 6090
Description: If there is no element in the range of a function, its domain must be empty. (Contributed by Alexander van der Vekens, 12-Jul-2018.)
Assertion
Ref Expression
f0rn0  |-  ( ( E : X --> Y  /\  -.  E. y  e.  Y  y  e.  ran  E )  ->  X  =  (/) )
Distinct variable groups:    y, E    y, Y
Allowed substitution hint:    X( y)

Proof of Theorem f0rn0
StepHypRef Expression
1 fdm 6051 . . 3  |-  ( E : X --> Y  ->  dom  E  =  X )
2 frn 6053 . . . . . . . . 9  |-  ( E : X --> Y  ->  ran  E  C_  Y )
3 ralnex 2992 . . . . . . . . . 10  |-  ( A. y  e.  Y  -.  y  e.  ran  E  <->  -.  E. y  e.  Y  y  e.  ran  E )
4 disj 4017 . . . . . . . . . . 11  |-  ( ( Y  i^i  ran  E
)  =  (/)  <->  A. y  e.  Y  -.  y  e.  ran  E )
5 df-ss 3588 . . . . . . . . . . . 12  |-  ( ran 
E  C_  Y  <->  ( ran  E  i^i  Y )  =  ran  E )
6 incom 3805 . . . . . . . . . . . . . 14  |-  ( ran 
E  i^i  Y )  =  ( Y  i^i  ran 
E )
76eqeq1i 2627 . . . . . . . . . . . . 13  |-  ( ( ran  E  i^i  Y
)  =  ran  E  <->  ( Y  i^i  ran  E
)  =  ran  E
)
8 eqtr2 2642 . . . . . . . . . . . . . 14  |-  ( ( ( Y  i^i  ran  E )  =  ran  E  /\  ( Y  i^i  ran  E )  =  (/) )  ->  ran  E  =  (/) )
98ex 450 . . . . . . . . . . . . 13  |-  ( ( Y  i^i  ran  E
)  =  ran  E  ->  ( ( Y  i^i  ran 
E )  =  (/)  ->  ran  E  =  (/) ) )
107, 9sylbi 207 . . . . . . . . . . . 12  |-  ( ( ran  E  i^i  Y
)  =  ran  E  ->  ( ( Y  i^i  ran 
E )  =  (/)  ->  ran  E  =  (/) ) )
115, 10sylbi 207 . . . . . . . . . . 11  |-  ( ran 
E  C_  Y  ->  ( ( Y  i^i  ran  E )  =  (/)  ->  ran  E  =  (/) ) )
124, 11syl5bir 233 . . . . . . . . . 10  |-  ( ran 
E  C_  Y  ->  ( A. y  e.  Y  -.  y  e.  ran  E  ->  ran  E  =  (/) ) )
133, 12syl5bir 233 . . . . . . . . 9  |-  ( ran 
E  C_  Y  ->  ( -.  E. y  e.  Y  y  e.  ran  E  ->  ran  E  =  (/) ) )
142, 13syl 17 . . . . . . . 8  |-  ( E : X --> Y  -> 
( -.  E. y  e.  Y  y  e.  ran  E  ->  ran  E  =  (/) ) )
1514imp 445 . . . . . . 7  |-  ( ( E : X --> Y  /\  -.  E. y  e.  Y  y  e.  ran  E )  ->  ran  E  =  (/) )
1615adantl 482 . . . . . 6  |-  ( ( dom  E  =  X  /\  ( E : X
--> Y  /\  -.  E. y  e.  Y  y  e.  ran  E ) )  ->  ran  E  =  (/) )
17 dm0rn0 5342 . . . . . 6  |-  ( dom 
E  =  (/)  <->  ran  E  =  (/) )
1816, 17sylibr 224 . . . . 5  |-  ( ( dom  E  =  X  /\  ( E : X
--> Y  /\  -.  E. y  e.  Y  y  e.  ran  E ) )  ->  dom  E  =  (/) )
19 eqeq1 2626 . . . . . . 7  |-  ( X  =  dom  E  -> 
( X  =  (/)  <->  dom  E  =  (/) ) )
2019eqcoms 2630 . . . . . 6  |-  ( dom 
E  =  X  -> 
( X  =  (/)  <->  dom  E  =  (/) ) )
2120adantr 481 . . . . 5  |-  ( ( dom  E  =  X  /\  ( E : X
--> Y  /\  -.  E. y  e.  Y  y  e.  ran  E ) )  ->  ( X  =  (/) 
<->  dom  E  =  (/) ) )
2218, 21mpbird 247 . . . 4  |-  ( ( dom  E  =  X  /\  ( E : X
--> Y  /\  -.  E. y  e.  Y  y  e.  ran  E ) )  ->  X  =  (/) )
2322exp32 631 . . 3  |-  ( dom 
E  =  X  -> 
( E : X --> Y  ->  ( -.  E. y  e.  Y  y  e.  ran  E  ->  X  =  (/) ) ) )
241, 23mpcom 38 . 2  |-  ( E : X --> Y  -> 
( -.  E. y  e.  Y  y  e.  ran  E  ->  X  =  (/) ) )
2524imp 445 1  |-  ( ( E : X --> Y  /\  -.  E. y  e.  Y  y  e.  ran  E )  ->  X  =  (/) )
Colors of variables: wff setvar class
Syntax hints:   -. wn 3    -> wi 4    <-> wb 196    /\ wa 384    = wceq 1483    e. wcel 1990   A.wral 2912   E.wrex 2913    i^i cin 3573    C_ wss 3574   (/)c0 3915   dom cdm 5114   ran crn 5115   -->wf 5884
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1722  ax-4 1737  ax-5 1839  ax-6 1888  ax-7 1935  ax-9 1999  ax-10 2019  ax-11 2034  ax-12 2047  ax-13 2246  ax-ext 2602  ax-sep 4781  ax-nul 4789  ax-pr 4906
This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-3an 1039  df-tru 1486  df-ex 1705  df-nf 1710  df-sb 1881  df-eu 2474  df-mo 2475  df-clab 2609  df-cleq 2615  df-clel 2618  df-nfc 2753  df-ral 2917  df-rex 2918  df-rab 2921  df-v 3202  df-dif 3577  df-un 3579  df-in 3581  df-ss 3588  df-nul 3916  df-if 4087  df-sn 4178  df-pr 4180  df-op 4184  df-br 4654  df-opab 4713  df-cnv 5122  df-dm 5124  df-rn 5125  df-fn 5891  df-f 5892
This theorem is referenced by: (None)
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