Topological and metric properties of convex sets #
We prove the following facts:
convex.interior: interior of a convex set is convex;convex.closure: closure of a convex set is convex;set.finite.compact_convex_hull: convex hull of a finite set is compact;set.finite.is_closed_convex_hull: convex hull of a finite set is closed;convex_on_dist: distance to a fixed point is convex on any convex set;convex_hull_ediam,convex_hull_diam: convex hull of a set has the same (e)metric diameter as the original set;bounded_convex_hull: convex hull of a set is bounded if and only if the original set is bounded.bounded_std_simplex,is_closed_std_simplex,compact_std_simplex: topological properties of the standard simplex;
Alias of real.convex_iff_is_preconnected.
Alias of real.convex_iff_is_preconnected.
Standard simplex #
Every vector in std_simplex 𝕜 ι has max-norm at most 1.
std_simplex ℝ ι is bounded.
std_simplex ℝ ι is closed.
std_simplex ℝ ι is compact.
Topological vector space #
If x ∈ s and y ∈ interior s, then the segment (x, y] is included in interior s.
If x ∈ s and x + y ∈ interior s, then x + t y ∈ interior s for t ∈ (0, 1].
In a topological vector space, the interior of a convex set is convex.
In a topological vector space, the closure of a convex set is convex.
Convex hull of a finite set is compact.
Convex hull of a finite set is closed.
If we dilate a convex set about a point in its interior by a scale t > 1, the interior of
the result contains the original set.
TODO Generalise this from convex sets to sets that are balanced / star-shaped about x.
Normed vector space #
Given a point x in the convex hull of s and a point y, there exists a point
of s at distance at least dist x y from y.
Given a point x in the convex hull of s and a point y in the convex hull of t,
there exist points x' ∈ s and y' ∈ t at distance at least dist x y.
Emetric diameter of the convex hull of a set s equals the emetric diameter of `s.
Diameter of the convex hull of a set s equals the emetric diameter of `s.
Convex hull of s is bounded if and only if s is bounded.